No.1768 交替合并字符串
给你两个字符串 word1 和 word2 。请你从 word1 开始,通过交替添加字母来合并字符串。如果一个字符串比另一个字符串长,就将多出来的字母追加到合并后字符串的末尾。
返回 合并后的字符串 。
示例 1:
text
输入:word1 = "abc", word2 = "pqr"
输出:"apbqcr"
解释:字符串合并情况如下所示:
word1: a b c
word2: p q r
合并后: a p b q c r
示例 2:
text
输入:word1 = "ab", word2 = "pqrs"
输出:"apbqrs"
解释:注意,word2 比 word1 长,"rs" 需要追加到合并后字符串的末尾。
word1: a b
word2: p q r s
合并后: a p b q r s
示例 3:
text
输入:word1 = "abcd", word2 = "pq"
输出:"apbqcd"
解释:注意,word1 比 word2 长,"cd" 需要追加到合并后字符串的末尾。
word1: a b c d
word2: p q
合并后: a p b q c d
提示:
- 1 <= word1.length, word2.length <= 100
- word1 和 word2 由小写英文字母组成
解题思路
实现
js
/**
* @param {string} word1
* @param {string} word2
* @return {string}
*/
var mergeAlternately = function (word1, word2) {
let len1 = word1.length;
let len2 = word2.length;
if (len1 === 0) return word2;
if (len2 === 0) return word1;
let maxLen = Math.max(len1, len2) - 1;
let str = "";
for (let i = 0; i <= maxLen; i++) {
str += (word1[i] || "") + (word2[i] || "");
}
return str;
};