No.200 岛屿数量

给你一个由 '1'（陆地）和 '0'（水）组成的的二维网格，请你计算网格中岛屿的数量。

岛屿总是被水包围，并且每座岛屿只能由水平方向和/或竖直方向上相邻的陆地连接形成。

此外，你可以假设该网格的四条边均被水包围。

示例 1：

输入：grid = [
["1","1","1","1","0"],
["1","1","0","1","0"],
["1","1","0","0","0"],
["0","0","0","0","0"]
]
输出：1

示例 2：

输入：grid = [
["1","1","0","0","0"],
["1","1","0","0","0"],
["0","0","1","0","0"],
["0","0","0","1","1"]
]
输出：3

提示：

• m == grid.length
• n == grid[i].length
• 1 <= m, n <= 300
• grid[i][j] 的值为 '0' 或 '1'

解题思路

实现

dfs 深度优先搜索

/**
 * @param {character[][]} grid
 * @return {number}
 */
var numIslands = function (grid) {
  if (grid.length === 0) return 0;
  let count = 0;
  const dfs = (grid, i, j) => {
    if (
      i < 0 ||
      i >= grid.length ||
      j < 0 ||
      j >= grid[0].length ||
      grid[i][j] === "0"
    )
      return;
    grid[i][j] = "0";
    dfs(grid, i + 1, j);
    dfs(grid, i - 1, j);
    dfs(grid, i, j + 1);
    dfs(grid, i, j - 1);
  };
  for (let i = 0; i < grid.length; i++) {
    for (let j = 0; j < grid[0].length; j++) {
      if (grid[i][j] === "1") {
        count++;
        dfs(grid, i, j);
      }
    }
  }
  return count;
};